Info

此问题已关闭。 请重新打开它进行编辑或回答。

Extracting the values from a cellarray

1 次查看（过去 30 天）
Reshma Ravi
Reshma Ravi 2017-6-12
关闭： MATLAB Answer Bot 2021-8-20
I have a cellarray that is 'GUUA' [2] 'UUAG' [2] 'UAGC' [2] 'CGCC' [2] then my problem is to find the probability (individual item/total count, here p(GUUA)=2/8)of occurence. How is this possible.
Thanks in advance.

此问题已关闭。

回答（1 个）

Michael Byrne
Michael Byrne 2017-8-4
编辑：Michael Byrne 2017-8-4
One way to accomplish this is to use the contains function to get a logical array describing the locations of a specific string (in your example, 'GUUA'), and then summing this array to obtain the number of occurrences of this string. The number of occurrences can then be divided by the length of the cell array to obtain the probability:
c = {'GUUA','GUUA','UUAG','UUAG',...
'UAGC','UAGC','CGCC','CGCC'}; % Your cell array
p = sum(contains(c,'GUUA'))/length(c); % Probability
  1 个评论
Akira Agata
Akira Agata 2017-8-4
Just a minor comment. If you want to count 'GUUA' exactly, I would recommend using strcmp, like:
p2 = sum(strcmp(c,'GUUA'))/length(c);

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by