How do I convert to nan all entries with a particular value in a cell array?

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Garima Sharma
Garima Sharma 2017-6-14
评论： Star Strider 2017-6-15
Each entry of the cell array is a matrix, and I want to convert to nan all entries, say, of value=1. Something like this: a=cellfun(@(x) x(x==1)=nan, a, 'un',0)
I tried to do this by creating a separate function, but I need to delete different values from the matrix assigned to each cell in the cell array, so I'm not sure how that would work. Can I just define a cell function like this?
function out = replaceval(in, val)
in(in==val) = NaN;
out = in;
end
  1 个评论
Rik
Rik 2017-6-14
This should work as far as I can tell. Keep in mind that you might have to replicate your second input as a cell if it is not the same for the cell you are using as first input.

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回答（1 个）

Star Strider
Star Strider 2017-6-14
I could not get this to work with only cellfun calls, and needed to use a loop.
This works:
C = {randi(9,5), randi(9,5), randi(9, 5)}; % Create Data
L = cellfun(@(x) x == 1, C, 'Uni',0); % Logical Arrays
C1 = C{1} % Display Initial Values
L1 = L{1} % Display Logical Arrays
for k1 = 1:size(C,2)
C{k1}(L{k1}) = NaN; % Replace With ‘NaN’
end
New_C1 = C{1} % Display Replaced Values
C1 =
2 4 9 3 5
1 8 1 3 7
4 5 2 3 4
5 3 7 6 1
6 5 7 6 8
L1 =
5×5 logical array
0 0 0 0 0
1 0 1 0 0
0 0 0 0 0
0 0 0 0 1
0 0 0 0 0
New_C1 =
2 4 9 3 5
NaN 8 NaN 3 7
4 5 2 3 4
5 3 7 6 NaN
6 5 7 6 8
Remove the ‘Display’ lines. They exist only to demonstrate the results.
  2 个评论
Garima Sharma
Garima Sharma 2017-6-15
Actually, this worked for me. I just have to make sure that the 2 cell arrays from which in and val are pulled have the same dimension.
B=cellfun(@replaceval, a, b, 'un',0)
function out = replaceval(in, val)
in(in==val) = NaN;
out = in;
end
Star Strider
Star Strider 2017-6-15
In my code, the logical cell arrays ‘L’ will by definition have the same dimensions as the matrices they are derived from. That is the advantage of calculating them in a separate step.

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