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ridge and bifurcation point count and location coding for Minutiae matching behalf of bellow code...could anyone help?

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indrani dalui
indrani dalui 2017-6-29
回答： linda Nankabirwa 2018-11-1
%Minutiae extraction
s=size(thin_image);
N=3;%window size
n=(N-1)/2;
r=s(1)+2*n;
c=s(2)+2*n;
double temp(r,c);
temp=zeros(r,c);bifurcation=zeros(r,c);ridge=zeros(r,c);
temp((n+1):(end-n),(n+1):(end-n))=thin_image(:,:);
outImg=zeros(r,c,3);%For Display
outImg(:,:,1) = temp .* 255;
outImg(:,:,2) = temp .* 255;
outImg(:,:,3) = temp .* 255;
for x=(n+1+10):(s(1)+n-10)
for y=(n+1+10):(s(2)+n-10)
e=1;
for k=x-n:x+n
f=1;
for l=y-n:y+n
mat(e,f)=temp(k,l);
f=f+1;
end
e=e+1;
end;
if(mat(2,2)==0)
ridge(x,y)=sum(sum(~mat));
bifurcation(x,y)=sum(sum(~mat));
end
end;
end;
% RIDGE END FINDING
[ridge_x ridge_y]=find(ridge==2);
len=length(ridge_x);
%For Display
for i=1:len
outImg((ridge_x(i)-3):(ridge_x(i)+3),(ridge_y(i)-3),2:3)=0;
outImg((ridge_x(i)-3):(ridge_x(i)+3),(ridge_y(i)+3),2:3)=0;
outImg((ridge_x(i)-3),(ridge_y(i)-3):(ridge_y(i)+3),2:3)=0;
outImg((ridge_x(i)+3),(ridge_y(i)-3):(ridge_y(i)+3),2:3)=0;
outImg((ridge_x(i)-3):(ridge_x(i)+3),(ridge_y(i)-3),1)=255;
outImg((ridge_x(i)-3):(ridge_x(i)+3),(ridge_y(i)+3),1)=255;
outImg((ridge_x(i)-3),(ridge_y(i)-3):(ridge_y(i)+3),1)=255;
outImg((ridge_x(i)+3),(ridge_y(i)-3):(ridge_y(i)+3),1)=255;
end
%BIFURCATION FINDING
[bifurcation_x bifurcation_y]=find(bifurcation==4);
len=length(bifurcation_x);
%For Display
for i=1:len
outImg((bifurcation_x(i)-3):(bifurcation_x(i)+3),(bifurcation_y(i)-3),1:2)=0;
outImg((bifurcation_x(i)-3):(bifurcation_x(i)+3),(bifurcation_y(i)+3),1:2)=0;
outImg((bifurcation_x(i)-3),(bifurcation_y(i)-3):(bifurcation_y(i)+3),1:2)=0;
outImg((bifurcation_x(i)+3),(bifurcation_y(i)-3):(bifurcation_y(i)+3),1:2)=0;
outImg((bifurcation_x(i)-3):(bifurcation_x(i)+3),(bifurcation_y(i)-3),3)=255;
outImg((bifurcation_x(i)-3):(bifurcation_x(i)+3),(bifurcation_y(i)+3),3)=255;
outImg((bifurcation_x(i)-3),(bifurcation_y(i)-3):(bifurcation_y(i)+3),3)=255;
outImg((bifurcation_x(i)+3),(bifurcation_y(i)-3):(bifurcation_y(i)+3),3)=255;
end
figure;imshow(outImg);title('Minutiae');
end
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采纳的回答

Walter Roberson
Walter Roberson 2017-7-1
Posting multiple copies of your question is not going to result in faster response.
Asking a specific question would help you get a response sooner.
http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
No, we are NOT going to write ridge point detection code for you. Some people might be willing to answer questions about the code if you have questions like "I ran it with this particular input and it produced this error message". We are probably not going to go read a bunch of papers and suggest algorithms for you either.
You do the research to find an algorithm. You make an attempt to implement it in MATLAB. You encounter an error in the MATLAB code that you cannot solve, and you post about that issue, including your code and the error message and a description of what you were doing. Someone might answer. (It will not be me; I do not do fingerprint recognition.)

更多回答（1 个）

linda Nankabirwa
linda Nankabirwa 2018-11-1
hello,can anyone tell how this minutiae extraction algorithm works,i need an explanation please because am trying to use but having problems while matching,thanks

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