How to plot the l2 norm circle?

7 次查看(过去 30 天)
Hi all,
I'm trying to visualize the l2 norm circle. It seems easy but I'm stuck. This is the code I write to plot the circle (based on x^2 + y^2 = 1):
clear; clc;
x = -1:0.01:1;
y = sqrt(1 - x .^ 2);
plot(x, y)
hold on
plot(y, x)
axis square
It gives me a figure like this:
apparently the left lower part is missing, what I do not understand is that both x and y are non-negative, why would l2 norm gives a full circle where left lower part is negative for both x and y?
Please forgive me if I did not explain mathematically enough.

采纳的回答

Torsten
Torsten 2017-7-6
theta=0:2*pi/100:2*pi;
x=cos(theta);
y=sin(theta);
plot(x,y)
Best wishes
Torsten.
  5 个评论
Torsten
Torsten 2017-7-6
clear;
clc;
x = -1:0.01:1;
y = sqrt(1 - x .^ 2);
plot(x, y)
hold on
plot(x, -y)
axis square
Best wishes
Torsten.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Surface and Mesh Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by