For loop inside for loop

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Isma_gp
Isma_gp 2017-8-15
回答： Arjun 2024-12-5
Hi, I have the following function that I am using with a single rho(1x654545) -attached. The result gives me the single peaks(1x1023). I would like to modify the script so that I can use as input rho(4x654545) and end up with the result peaks(4x1023).
Can I get some help? Thanks
x = diff(sign(rho));
indx = find(x>0);
for jj=2:length(indx);
tmp = rho(indx(jj-1):(indx(jj)));
test = dt*(indx(jj)-indx(jj-1));
peaks(jj) = max(tmp);
end
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Isma_gp
Isma_gp 2017-8-15
Yes, that is true. The number of values >0 could vary.
Adam
Adam 2017-8-15
In that case you'd have to use a cell array or a 2d numeric array with enough rows for the case with most peaks and leave NaNs in the extra rows for the other columns.

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回答（1 个）

Arjun
Arjun 2024-12-5
Hi @Isma_gp,
I see that currently you are processing a row vector to extract a row vector containing peaks and want to extend this functionality for a matrix.
Since each row of the matrix can have different number of peaks and hence returning a matrix of peaks will not be suitable. You can return a “cell array” instead which will contain same number of rows as in the input matrix and a single column containing a vector of peaks.
Kindly refer to the code below for better understanding:
num_rows = size(rho, 1);
% Initialize a cell array
peaks = cell(num_rows, 1);
for i = 1:num_rows
x = diff(sign(rho(i, :)));
indx = find(x > 0);
% Temporary array to collect peaks for the current row
row_peaks = [];
for jj = 2:length(indx)
tmp = rho(i, indx(jj-1):indx(jj));
% Append the peak to the temporary array
row_peaks(end+1) = max(tmp);
end
% Store the peaks for the current row in the cell array
peaks{i} = row_peaks;
end
Kindly refer to the attached documentation link understand more about the “cell array”: https://www.mathworks.com/help/releases/R2021a/matlab/ref/cell.html
I hope this will help!

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