finding distance from text data for latitude/longitude and creating new column of data for distance

Question

douglas 2012-4-13

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https://ww2.mathworks.cn/matlabcentral/answers/35423-finding-distance-from-text-data-for-latitude-longitude-and-creating-new-column-of-data-for-distance

Hello all,

I have a series of text files with latitude/longitude data, in seperate columns, and time in another column. I would liek to use the latitude/longitude data to make a distance vs. time plot.

formula for distance based on lat/long:

R = earth’s radius (mean radius = 6,371km)
Δlat = lat2− lat1
Δlong = long2− long1
a = sin²(Δlat/2) + cos(lat1).cos(lat2).sin²(Δlong/2)
c = 2.atan2(√a, √(1−a))
d = R.c

The syntax isnt correct above as its not matlab code, just a formula on the internet.

How would I go about defining a new column of data (distance) by having it find the difference between every point of lat and long and then run the other basic operations to find distance?

the data in the text would follow this format;

Latitude   Longitude  
8885857  -2.159813307
888588  -2.159810551
88858751  -2.159811237
88858772  -2.159810981
88858774  -2.159810887
88858765  -2.159811144
88858779  -2.159810991
88858747  -2.159811489
88858758  -2.159811597
88858755  -2.15981158
88858725  -2.159811985
88858732  -2.159812218

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douglas 2012-4-13

would a double for loop work?

say

for i = 2:length(Latitude);

for j = 1:length(Latitude);

dellat = Latitude(i)-Latitude(j);

dellong = Longitude(i)-Longitude(j);

end

and then relate dellat and dellong with the above formula to find an array for the value of d? I haven't gotten the chance to test it yet.

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Answer 1

bym 2012-4-13

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https://ww2.mathworks.cn/matlabcentral/answers/35423-finding-distance-from-text-data-for-latitude-longitude-and-creating-new-column-of-data-for-distance#answer_44394

在 MATLAB Online 中打开

the diff() function will calculate the difference for you without a loop. Here is a start:

loc = [51.8885857  -2.159813307;...
888588  -2.159810551;...
88858751  -2.159811237;...
88858772  -2.159810981;...
88858774  -2.159810887;...
88858765  -2.159811144;...
88858779  -2.159810991;...
88858747  -2.159811489;...
88858758  -2.159811597;...
88858755  -2.15981158;...
88858725  -2.159811985;...
88858732  -2.159812218];
dloc = diff(loc);
a = sind(dloc(:,1)./2).^2 + ...
    cosd(loc(1:end-1,1)).*cosd(loc(2:end,1)).*sind((dloc(:,2)./2).^2);

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douglas 2012-4-18

This seemed to work out for me, is there a way to add each new data point as a sum of the previous ones? like mapping out a flight and having the last data point be the added sum? my results right now give me the distance traveled per data point, so it fluctuates based on speed etc. I'd like a total distance traveled

douglas 2012-4-18

nevermind I found that cumsum(distance) worked well.

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Answer 2

Andrei Bobrov 2012-4-13

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/35423-finding-distance-from-text-data-for-latitude-longitude-and-creating-new-column-of-data-for-distance#answer_44395

在 MATLAB Online 中打开

use function distance from Mapping Toolbox

LatLon = [51.8885857  -2.159813307
51.888588  -2.159810551
51.88858751  -2.159811237
51.88858772  -2.159810981
51.88858774  -2.159810887
51.88858765  -2.159811144
51.88858779  -2.159810991
51.88858747  -2.159811489
51.88858758  -2.159811597
51.88858755  -2.15981158
51.88858725  -2.159811985
51.88858732  -2.159812218]
s1  = size(LatLon,1)
k = nchoosek(1:s1,2)
d = deg2km(distance(LatLon(k(:,1),1),LatLon(k(:,1),2),...
                            LatLon(k(:,2),1),LatLon(k(:,2),2))) ;
dout = zeros(s1);
dout(tril(true(s1),-1)) = d;
dout = dout + dout';

variant without Mapping Toolbox

L = [51.8885857  -2.159813307
51.888588  -2.159810551
51.88858751  -2.159811237
51.88858772  -2.159810981
51.88858774  -2.159810887
51.88858765  -2.159811144
51.88858779  -2.159810991
51.88858747  -2.159811489
51.88858758  -2.159811597
51.88858755  -2.15981158
51.88858725  -2.159811985
51.88858732  -2.159812218];
R = 6371; 
dla = abs(bsxfun(@minus,L(:,1),L(:,1)'));
dlo = abs(bsxfun(@minus,L(:,2),L(:,2)'));
lac = cosd(L);
a = sind(dla/2).^2 + lac(:,1)*lac(:,1)'.*sind(dlo/2).^2;
d = R*2*atan2(sqrt(a), sqrt(1 - a)) ;