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Lagrange Multipliers

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Dhurgham Kadhim
Dhurgham Kadhim 2012-4-15
评论： Divy 2023-1-21
Use the Lagrange mulipliers to find the points on the parabola y=x^2+2x which are the closest to the point(-1,0).
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Walter Roberson
Walter Roberson 2012-4-15
http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

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采纳的回答

bym
bym 2012-4-16
here is a nudge to solving your problem
syms x y L
d = ??? % for you to fill out; distance from (-1,0)
g = d+L*(x^2+2*x-y) % constraint for given parabola
% additional operations here
show some effort, and some additional help may be forthcoming

更多回答（1 个）

Richard Brown
Richard Brown 2012-4-15
This is not a Matlab question, it's a calculus homework problem. Define a function f(x,y) that you want to minimise, a constraint c(x,y) = 0, and then solve c(x,y) = 0, together with
grad f = lambda grad c
for x, y, and lambda.
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Richard Brown
Richard Brown 2012-4-16
It's pretty straightforward to solve by hand - I recommend you do it that way, you'll learn more if you do.

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