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Error encountered for numerical integration inside for loop.

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Jay
Jay 2017-9-12
回答： Walter Roberson 2017-9-12
So this is the code I'm trying to run -
q=10e8:10000:20e9;
s=length(q);
epso = 8.8 *10.^-12;
epsr=5.7;
ro=3.63*(10.^-3);
epsl = 2.5;
ri=1.13*(10.^-3);
copen = (epso/sqrt(epsr)*log(ro/ri));
cload= (epsl/sqrt(epsr)*log(ro/ri));
t = zeros(1,s);
for f = 1:length(q)
fun = @(x)(((((besselj(0,(2*pi*q(f))/(3e8))*x*ro)-besselj(0,(2*pi*q(f))/(3e8))*x*ri)).^2)./x).*freload(x,q)));
y(f) = copen*abs(integral(fun,0,Inf));
t(f)=(1-y(f))/(1+y(f));
end
plot (q,t);
where the function freload is
function f = freload(x,q)
epsl=3.4;
f=(1./sqrt(epsl-(x.^2))).*(1+exp(-2*1i*2*pi*q./(3e8).*sqrt(epsl-(x.^2))))./((1-exp(-2*1i*2*pi*q/(3e8).*sqrt(epsl-(x.^2)))));
end
The errors I get are as follows -
Error using integralCalc/finalInputChecks (line 515)
Output of the function must be the same size as the input. If FUN is an array-valued integrand, set the
'ArrayValued' option to true.
Error in integralCalc/iterateScalarValued (line 315)
finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 83)
[q,errbnd] = vadapt(@AToInfInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in numint (line 14)
y(f) = copen*abs(integral(fun,0,Inf));
The program seems to be giving an output for other functions. Any help would be appreciated greatly.

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采纳的回答

Walter Roberson
Walter Roberson 2017-9-12
Your line
fun = @(x)(((((besselj(0,(2*pi*q(f))/(3e8))*x*ro)-besselj(0,(2*pi*q(f))/(3e8))*x*ri)).^2)./x).*freload(x,q)));
calls freload() passing in all of q, instead of q(f)

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