replacements = {[1 0], [0 1]}; %or {'10', '01'}
result = replacements(1+A);
This will give a cell array of values. A cell array is required if you need to preserve the leading '0' of '01': if you were to use
replacements = [10 01];
then
>> replacements(1+A)
ans =
1 10 10
10 1 10
1 10 10
