Error: In an assignment A(I) = B, the number of elements in B and I must be the same.

1 次查看(过去 30 天)
Hello everyone. Here is the code that gives me the following error:
In an assignment A(I) = B, the number of elements in B and I must be the same.
Error in SeasonalityLVEbif>Preypred (line 33)
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
The code :
function SeasonalityLVEbif
rect=[200 80 700 650];%fix the window size and position
set(0,'defaultfigureposition',rect);
global alpha1 b P theta q c a e d
alpha1=0.5; b=1.2; P=0.025; theta= 0.03;q=0.0038; c= 0.81; a= 0.25; e=0.8; d=0.25;
option=odeset('AbsTol',1e-11,'RelTol',1e-11);
inc=[0.01:1:220]';
time=[ inc ] ;
limit=[200:1:220];
ymin=[];
ymax=[];
for Ke=0.01:0.05:2,
IC=[1.5 1 0 0.5 0.25 ];
[t,U]=ode45(@Preypred,time,IC);
u1=U(limit,1);
ymin=[ymin,min(u1)];
ymax=[ymax,max(u1)];
end
X=0.01:0.05:2;
figure
plot(X, ymin,'g.',X, ymax,'k.');
legend('grazer min','grazer max'),
hold on
xlim([0.01 2]);
title('Bifurcation diagram for LVE model','FontSize',12)
xlabel('Ke, the equilibrium carrying capacity');
ylabel('grazer','Rotation',90);
function [Ydot] = Preypred(t,Y)
global alpha1 Ke b P theta q c a e d
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
Ydot(2) =Y(2)*(1-Y(2)^2-Y(3)^2)-2*pi*Y(3)/6;
Ydot(3) = Y(3)*(1-Y(2)^2-Y(3)^2)+2*pi*Y(2)/6;
Ydot(4) = b*Y(4)*(1-Y(4)/(min(Y(1),(P-theta*Y(5))/q)))-c*Y(4)*Y(5)/(a+Y(4));
Ydot(5) = e*min(1,((P-theta*Y(5))/Y(4))/theta)*c*Y(4)*Y(5)/(a+Y(4))-d*Y(5);
Ydot=Ydot';
Could you please help me to fix it?
  1 个评论
Stephen23
Stephen23 2017-10-15
编辑:Stephen23 2017-10-15
Note that you would be better off replacing the global variables with simply passing a structure of those values. Using global is almost always the worst way to pass data between workspaces.

请先登录,再进行评论。

采纳的回答

KSSV
KSSV 2017-10-16
function SeasonalityLVEbif
rect=[200 80 700 650];%fix the window size and position
set(0,'defaultfigureposition',rect);
% global alpha1 b P theta q c a e d
values = struct ;
values.alpha1=0.5;
values.b=1.2;
values.P=0.025;
values.theta= 0.03;
values.q=0.0038;
values.c= 0.81;
values.a= 0.25;
values.e=0.8;
values.d=0.25;
option=odeset('AbsTol',1e-11,'RelTol',1e-11);
inc=[0.01:1:220]';
time=[ inc ] ;
limit=[200:1:220];
ymin=[];
ymax=[];
for Ke=0.01:0.05:2
IC=[1.5 1 0 0.5 0.25 ];
[t,U]=ode45(@Preypred,time,IC,[],values,Ke);
u1=U(limit,1);
ymin=[ymin,min(u1)];
ymax=[ymax,max(u1)];
end
X=0.01:0.05:2;
figure
plot(X, ymin,'g.',X, ymax,'k.');
legend('grazer min','grazer max'),
hold on
xlim([0.01 2]);
title('Bifurcation diagram for LVE model','FontSize',12)
xlabel('Ke, the equilibrium carrying capacity');
ylabel('grazer','Rotation',90);
function [Ydot] = Preypred(t,Y,values,Ke)
Ydot = zeros(1,5) ;
alpha1 = values.alpha1 ;
b = values.b ;
P = values.P ;
theta = values.theta ;
q = values.q ;
c = values.c ;
a = values.a ;
e = values.e ;
d = values.d ;
Ydot(1) =(alpha1*(Ke-Y(1)))+Ke*pi*Y(2)/6;
Ydot(2) =Y(2)*(1-Y(2)^2-Y(3)^2)-2*pi*Y(3)/6;
Ydot(3) = Y(3)*(1-Y(2)^2-Y(3)^2)+2*pi*Y(2)/6;
Ydot(4) = b*Y(4)*(1-Y(4)/(min(Y(1),(P-theta*Y(5))/q)))-c*Y(4)*Y(5)/(a+Y(4));
Ydot(5) = e*min(1,((P-theta*Y(5))/Y(4))/theta)*c*Y(4)*Y(5)/(a+Y(4))-d*Y(5);
Ydot=Ydot';

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Argument Definitions 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by