creating a feature matrix

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Mahmoud Zeydabadinezhad
编辑： Jos (10584) 2017-10-30
Hi, I have a cell array P of size 5000x1 which each element of it is another cell array of variable size (1xDIM). There is another cell array, vocab, of size 1x2000. The task is to create a matrix X of size 5000x2000 where X(i,j)=1 if vocab{1,j} is in P{i,1}. (P{i,1} is a cell array itself, not a single cell). I did this but the result is not correct:
for n=1:length(P)
for m=1:length(vocab)
if (strcmp(P{n},vocab{m}))
X(n,m) = 1;
else
X(n,m) = 0;
end
end
end
Thanks,

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回答（1 个）

Jos (10584)
Jos (10584) 2017-10-29
编辑：Jos (10584) 2017-10-30
I think this should work:
vocab = {'A','B','C','D'} % 1-by-M cell array of strings
P = {{'A'} ; {'C','A'} ; {'B','A'}} % N-by-1 cell array of cell array of strings
X = arrayfun(@(k) ismember(vocab, P{k,1}), 1:size(P,1), 'un', 0) ;
X = cat(1,X{:}) % a N-by-M logical array

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