Hi everyone, Can you help me

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SULE SAHIN
SULE SAHIN 2017-10-30
评论： Walter Roberson 2018-4-27
If we list all the natural numbers up to 15 that are multiples of 3 or 5, we get 3, 5, 6, 9, 10, 12 and 15. The sum of these multiples is 60. Write a function called sum3and5muls that returns the sum of all the unique multiples of 3 or 5 up to n where n is a positive integer and the only input argument of the function. (Credit: Project Euler) I do anything the above question. I dont know loop yet. Can you give some hints please?

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回答（4 个）

Jos (10584)
Jos (10584) 2017-10-30
I give you a suggestion
tf = false(1,n)
tf(x:x:n) = true
w = find(tf)
sum(w)
Walter Roberson
Walter Roberson 2017-10-30
Hint: 3:3:15
Andrei Bobrov
Andrei Bobrov 2017-10-30
sum([3:3:n,5:5:n]);
SULE SAHIN
SULE SAHIN 2017-10-30
编辑：Walter Roberson 2017-10-30
function sumof = sum3and5muls(n)
sumof = sum([3:3:n])+sum([5:5:n])-sum([15:15:n]);
Problem 8 (sum3and5muls): Testing with argument(s) 1 Feedback: Your program made an error for argument(s) 1
Your solution is _not_ correct.
What is wrong in my code?
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Walter Roberson
Walter Roberson 2017-10-30
No, the problem talks about unique multiples.
Walter Roberson
Walter Roberson 2017-10-30
SULE SAHIN: your code looks acceptable to me.

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