Extreact Information from a String
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Hello, I do have the following Code
d = dir('/home/user/Documents/Data*.inp');
names = {d.name}
which gives me an Array of Strings.
names(1) is like = "Data_c11_t3.322111_id01111_Units.inp"
names(2) is like = "Data_c101_t4.32111_id01112_Units.inp"
etc.
Now I want to extract the time, which is in the name after "t". How can I extract the time in such a format?
Any suggestions?
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采纳的回答
KL
2017-11-2
编辑:KL
2017-11-2
regexp would be the best idea, I've no big experiences with it, I'll give it a shot anyway,
names = {'Data_c11_t3.322111_id01111_Units.inp';'Data_c101_t4.32111_id01112_Units.inp'};
t = regexp(names,'[0-9]+\.+[0-9*]+','match')
4 个评论
Guillaume
2017-11-3
To each their own opinion of course. Regular expressions are designed to extract specific patterns in strings, which, in my opinion is exactly the problem at hand.
更多回答(2 个)
Jos (10584)
2017-11-3
Use a sscanf to read the number between the _t and _id, ignoring the varying number after the _c. Use cellfun to apply this to all cells:
names = {'Data_c11_t3.322111_id01111_Units.inp' ; 'Data_c101_t4.32111_id01112_Units.inp'} ;
T = cellfun(@(N) sscanf(N,'Data_c%*d_t%f_id'), names) % "%*d" = the * means skip
3 个评论
Coco Newton
2019-8-2
@Jos, this is a great answer
How would I adapt the sscanf formatSpec to extract 130 as a numeric value from this string? I have attached the string array variable that this is example string is taken from.
'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
Many thanks!
Jos (10584)
2019-8-5
Thanks :-) Something along these lines should work for your input
str = 'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
A = sscanf(str, 'Position: (%*f|%*f|%*f)Rotation: (%*d | %d | %*d)')
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