How to replace repeating no.s in an array by distinct no.?

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Abdul Gaffar
Abdul Gaffar 2017-11-3
编辑： Guillaume 2017-11-3
Let n=10 Consider array A={7,6,3,5,3,6,6,2,9,6} Algorithm: replace the repeating no. by its maximum unused value & I want all no.s between 1 & 10. How can it be done??
  1 个评论
Guillaume
Guillaume 2017-11-3
I'm assuming that
A = [7,6,3,5,3,6,6,2,9,6]
i.e. it is a regular matrix, not a cell array as you've written.
What do you want as an output?

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2017-11-3
A=[7,6,3,5,3,6,6,2,9,6]
[a,b] = unique(A,'first');
out = zeros(10,1);
out(b) = a;
out(out==0) = setdiff(1:10,a)

更多回答（2 个）

KSSV
KSSV 2017-11-3
编辑：KSSV 2017-11-3
A = randperm(10) ;
Guillaume
Guillaume 2017-11-3
编辑：Guillaume 2017-11-3
If I understood correctly:
A = [7,6,3,5,3,6,6,2,9,6]
[~, ~, subs] = unique(A);
idxtoreplace = accumarray(subs, (1:numel(A))', [], @(idx) {idx(2:end)});
idxtoreplace = vertcat(idxtoreplace{:});
replacementvals = setdiff(1:numel(A), A);
A(idxtoreplace) = replacementvals(1:numel(idxtoreplace));
Note that which of the duplicate gets replaced and by which value may change with matlab versions, but you're guaranteed that all but 1 of the duplicated values is replaced by an unused value.

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