Calculations with functions in cells

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Spyros Polychronopoulos 2017-11-9

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评论： Spyros Polychronopoulos 2018-5-5

Hello I have the matrix d and I would like to calculate the minimum value in the first cell d{1}. But I have a mistake somewhere:

A1=rand(64,1);
A2=rand(2,2);
for k = 1:1:2
  d{k}=@(z) (((A1(:,1)-A2(k,1)).^2)+((z-A2(k,2)).^2)); 
end 
z0=[0,0];
fminsearch(d{1},z0)

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Spyros Polychronopoulos 2017-11-13

在 MATLAB Online 中打开

Hi Robert Uhlig, First of all thank you for coming back to me! As you know from the previous post I am looking to find a number of solutions for in-depended values that's why I was trying to have z1,z2,...,zn variables. But you proved that you get the same sets of solutions if you use one variable z. But I tried the below to get z1,z2,...,z64

A1=rand(64,1);
A2=rand(2,2);
for k = 1:1:2
  for kk=1:1:64
  eval(cat(2,'d{kk,k} = @(z',num2str(kk),') (((A1(kk,1)-A2(k,1)).^2)+((z',num2str(kk),'-A2(k,2)).^2));'));
  end
end

Then adding them up (doesn't work with sum or plus)

for k = 1:1:2
  d1{k}=sum(d{:,k});
end

And then the optimiser

z0=zeros(64,1);
fminsearch(d1{1,1},z0)

I was looking your 3rd Example. Could I get the sum and optimiser in the end? I don't see how am I going to sum up the columns that way because the final array is 1x2. I also tried to use the optimiser but didn't work:

A1=rand(64,1);
A2=rand(2,2);
for k = 1:1:2
d{k}=@(z) (((A1(:,1)-A2(k,1)).^2)+((z-A2(k,2)).^2)); 
end 
z0=zeros(64,1);
fminsearch(d{1},z0)

Juliana Tavora 2018-5-5

Hi Spyros Polychronopoulos, did you find a solution for your question? I am having a similar problem.

I have 2 arrays (200x200 each) and trying to make a sum of functions.

Spyros Polychronopoulos 2018-5-5

Hi Juliana, I don't understand your issue. could you send here an example code?

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