Using regexp to match multiple substrings, two questions
11 次查看(过去 30 天)
显示 更早的评论
Hi all, Simple two part question.
1) I have a function where regexp needs to match two terms in a string.
st1='This string is going to be searched'
Expression should evaluate to True if st1 contains 'going' and 'search'.
I stole the following syntax from an old StackOverflow thread. I understand why it works. My question is, why is the '^' necessary? What is it doing?
hasMatch=~isempty(regexp(st1,'^(?=.*going).*(?=.*search).*'))
2) This code will be in a function. I would like to generalize it to any number of substrings that need to be matched. I understand varargin, but I'm not clever enough with regexp to code an arbitrary number of substrings that must be matched. Any help would be welcome.
Thanks!
-Aram
3 个评论
Stephen23
2017-11-27
@Aram Schiffman: a regular expression is fundamentally order-dependent. You should consider other solutions.
采纳的回答
Stephen23
2017-11-27
编辑:Stephen23
2017-11-27
You do not need to use regexp to fulfill the given requirements:
>> st1 = 'This string is going to be searched';
>> fun = @(s)~isempty(strfind(st1,s));
>> all(cellfun(fun,{'going','search'}))
ans = 1
>> all(cellfun(fun,{'going','elephant'}))
ans = 0
You can put this into a function, and provide as many inputs as you want:
function out = areinstr(str,varargin)
fun = @(s)~isempty(strfind(str,s));
out = all(cellfun(fun,varargin));
end
and tested:
>> areinstr(st1,'going','search','This')
ans = 1
>> areinstr(st1,'going','search','This','string')
ans = 1
>> areinstr(st1,'going','search','This','string','antelope')
ans = 0
3 个评论
Stephen23
2017-11-27
"I thought there was a way for them not to beI thought there was a way for them not to be"
There are some hacks that can be used to make them order-independent, but they make expression much more complex and slow.
Remember to accept the answer that best helps you to resolve your original question. That is the easiest way to show your thanks to the volunteers who helped you.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!