XCORR of two harmonic signals has a triangular shape. Why?
7 次查看(过去 30 天)
显示 更早的评论
Hello! I have two signals (H and Z), which are almost harmonic. Both vectors contain 4018 elements each (I attach the picture). I want to calculate cross correlation between them, and what I get is shown on the second picture. My code is simple:
C=xcorr(H,Z,'coeff')
What can be the reason of such triangular shape? I tried to calculate xcorr of sin and cos, and even added trend to one of them, but it's not triangular, it must be also harmonic... Why can this happen?
0 个评论
回答(1 个)
Christoph F.
2017-11-30
编辑:Christoph F.
2017-11-30
> What can be the reason of such triangular shape?
The reason is that both signals have a significant DC component/offset. Try removing it. For example
C=xcorr(H-mean(H),Z-mean(Z),'coeff')
or a more sophisticated method like highpass filtering or forward-backward highpass filtering with filtfilt.
0 个评论
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!