How do I generate a uniform random number from a 2d matrix to form a 3d matrix

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Onovo
Onovo 2017-12-7
评论： Onovo 2017-12-7
I have a vector A, such that A is 48X1, I need to create another matrix B from A, such that B is 48X1X5000 (i.e. a 3D matrix). Now I want all element in the first row of matrix B to be a random number that is within 0.8 times and 1.2 times the element in the first row of matrix A. All element in the second row of matrix B to be a random number that is within 0.8 times and 1.2 times the element in the 2nd row of matrix A. All element in the third row of matrix B to be a random number that is within 0.8 times and 1.2 times the element in the third row of matrix A, and so on till the 48th row. Remember B is a 3D matrix of 48 by 1 by 5000. Thank you. Looking forward to your support.

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James Tursa
James Tursa 2017-12-7
编辑：James Tursa 2017-12-7
E.g., later versions of MATLAB:
A = whatever;
f1 = 0.8;
f2 = 1.2;
n = 5000;
B = A .* (f1 + rand([size(A) n])*(f2-f1)));
Or earlier versions of MATLAB:
B = bsxfun(@times,A,f1 + rand([size(A) n])*(f2-f1));

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