Indexing cannot yield multiple results

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Stelios Fanourakis
Stelios Fanourakis 2017-12-11
回答： Steven Lord 2017-12-11
What is the wrong in this code?
WL2R=0;
if (nargin < 2)
[Rmin Rmax] = WL2R(Win, LevV);
elseif numel(disprange) == 0
[Rmin Rmax] = WL2R(Win, LevV);
else
LevV = (double(disprange(2)) + double(disprange(1))) / 2;
Win = double(disprange(2)) - double(disprange(1));
WLAdjCoe = (Win + 1)/1024;
[Rmin Rmax] = WL2R(Win, LevV);
end
  2 个评论
Jos (10584)
Jos (10584) 2017-12-11
How are we supposed to know ... :) Since you get the error message or incorrect result, show that to us!
Stelios Fanourakis
Stelios Fanourakis 2017-12-11
The first line [Rmin Rmax] = WL2R(Win, LevV); Gets the error (see topic)

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回答（1 个）

Steven Lord
Steven Lord 2017-12-11
WL2R=0;
if (nargin < 2)
[Rmin Rmax] = WL2R(Win, LevV);
The third line of that code segment may be an attempt to call a function WL2R. But because of the first line of that segment, it is instead interpreted as an attempt to index into the variable WL2R, and as the error message correctly states indexing cannot yield multiple results.
If you intended to call that function, don't define a variable with the same name. If you intended to index the variable, specify only one expression on the left side of the equals sign.

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