Precision lost when change numbers to string

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H R
H R 2017-12-13
评论： Walter Roberson 2017-12-14
Hi I am trying to use the following to generate a string. A is is 1D array containing 4 real numbers that have large decimal precisions
A=[0.000002101, 0.000000225567 ,1.20004136789, 66.000052353]
ST=strjoin( string('Hi ') + A.', newline )
However string 'ST' trims or rounds off my numbers. How can I create the string ST with exact numbers in A?
fid = fopen('ny.txt','wt');
fprintf(fid, '%s', ST);
fclose(fid);

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采纳的回答

Philip Borghesani
Philip Borghesani 2017-12-14
Similar to how you were doing it:
ST=join("Hi " + num2str(A',"%1.12e"), newline )
ST =
"Hi 2.101000000000e-06
Hi 2.255670000000e-07
Hi 1.200041367890e+00
Hi 6.600005235300e+01"
Or using sprintf like Walter suggested:
>> sprintf('Hi %1.12e\n',A)
ans =
'Hi 2.101000000000e-06
Hi 2.255670000000e-07
Hi 1.200041367890e+00
Hi 6.600005235300e+01
'
Note that the first method returns a string without a trailing newline and sprintf returns a character vector with one.

更多回答（1 个）

Walter Roberson
Walter Roberson 2017-12-14
I am not able to find any documentation establishing that using + between string and number is intended to work at all -- though I know that it is intended to work.
You will need to use sprintf() to do fine-grained formatting of numbers into strings.
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Steven Lord
Steven Lord 2017-12-14
The description of the input arguments for plus in the documentation includes a similar statement.
"If one input is a string array, then the other input can be a numeric, logical, character, string, or cell array."
But I can understand why Walter was unable to find this information -- it's not as visible as it could be. I have created an enhancement request for the documentation staff.
Walter Roberson
Walter Roberson 2017-12-14
The information about + for strings cannot be found from the documentation of the string data type; it is not indexed in the operations.
The help string.plus and the plus documentation do mention that those kinds of mixes are permitted, but say nothing about what the output will be in such a case. I explored last night and found that there is no single format specification that is used, and that the result depends upon the mix of numbers:
>> "Hi " + [1.234567890123456]
ans =
"Hi 1.2346"
so 4 digits after the decimal for this entry?
>> "Hi " + [1.234567890123456;A.']
ans =
5×1 string array
"Hi 1.23457"
"Hi 2.101e-06"
"Hi 2.25567e-07"
"Hi 1.20004"
"Hi 66.0001"
so 5 digits after the decimal for that same entry?
>> "Hi " + [1.234567890123456; 123456789012345 ./ 10.^(1:30).']
ans =
31×1 string array
"Hi 1.234567890123456"
"Hi 12345678901234.5"
"Hi 1234567890123.45"
"Hi 123456789012.345"
"Hi 12345678901.2345"
"Hi 1234567890.12345"
"Hi 123456789.012345"
"Hi 12345678.9012345"
"Hi 1234567.89012345"
"Hi 123456.789012345"
"Hi 12345.6789012345"
"Hi 1234.56789012345"
"Hi 123.456789012345"
"Hi 12.3456789012345"
"Hi 1.23456789012345"
"Hi 0.123456789012345"
"Hi 0.0123456789012345"
"Hi 0.00123456789012345"
"Hi 0.000123456789012345"
"Hi 1.23456789012345e-05"
"Hi 1.23456789012345e-06"
"Hi 1.23456789012345e-07"
"Hi 1.23456789012345e-08"
"Hi 1.23456789012345e-09"
"Hi 1.23456789012345e-10"
"Hi 1.23456789012345e-11"
"Hi 1.23456789012345e-12"
"Hi 1.23456789012345e-13"
"Hi 1.23456789012345e-14"
"Hi 1.23456789012345e-15"
"Hi 1.23456789012345e-16"
so 14 digits after the decimal for the same 1.* value ??

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