How do I change the yaxis exponent when using a double y-axis plot?

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Pieter Spruijt
Pieter Spruijt 2017-12-21
评论： Ankit Labh 2023-5-18
When use a plot with a y-axis on the left and a y-axis on the right, I can't figure out how to change the exponent of one y-axis. For example, when using the following code:
x = [1 2 3];
y1 = [2 6 4; 3 5 4; 5 7 8];
y2 = 100*[5 5 3; 3 4 7; 5 6 3];
figure
yyaxis left
plot(x,y1)
yyaxis right
plot(x,y2)
ax = gca;
yyaxis left
ax.YDir = 'reverse';
yyaxis right
ax.YAxis.Exponent = 3;
So I can change the direction of the left axis, but when I change the exponent of the right axis, I get the following error: "Expected one output from a curly brace or dot indexing expression, but there were 2 results. Error in test line 19) ax.YAxis.Exponent = 3;"

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回答（1 个）

Ramnarayan Krishnamurthy
Try setting the exponent as follows:
ax.YAxis(2).Exponent=3;
instead of ax.YAxis.Exponent = 3;
This sets the exponent of the second Y Axis (the one to the right) to 3.
  2 个评论
Christof Tschannen
Christof Tschannen 2022-7-26
I am so gratefull for that comment! I was looking for a long time for a solution of having two y-axis, one logarithmic, the other linear and I could not get rid of the scientific notation on the logarithmic y-axis.
Btw, I was using this command that I picked up in another forum post and added the axis indicator to it:
ax=gca
ax.YAxis(1).TickLabels = compose('%g', ax.YAxis(1).TickValues);
The code worked when I had only one axis, but with two I always got an error. With the specification (1) it finally worked :)
Again, thanks a lot!

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