array manipulation using location

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SSG_newbiecoder
SSG_newbiecoder 2017-12-25
编辑： SSG_newbiecoder 2017-12-26
Hello, I have an array X and another array Y which has some of the indices in array X. I need a new array which will have the X value in the corresponding Y element(index location in X) and zero otherwise. can anybody help me? this is what I tried but it's not working. I'm only getting one value.
X=[11 22 51 28 93 11 124 153 165 176 17 18 19 20];
iY=[1 3 5 9];
for m=1:length(X)
for n=1:length(iY)
if m~=iY(n)
combined_matrix(m)=0;
elseif m==iY(n)
combined_matrix(m)=X(iY(n));
end
end
end

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Birdman
Birdman 2017-12-25
编辑：Birdman 2017-12-25
Do you mean this?
X(~ismember(1:numel(X),iY))=0
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Birdman
Birdman 2017-12-26
编辑：Birdman 2017-12-26
Yes but you should avoid using for loops while you can. My solution is really simple. Of course preallocation is something you should do for that case but for loop is not necessary here.
SSG_newbiecoder
SSG_newbiecoder 2017-12-26
编辑：SSG_newbiecoder 2017-12-26
@Birdman OK,thank you..

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