Fill data with NaN for missing days

1 次查看（过去 30 天）
Sagar
Sagar 2017-12-25
编辑： Sagar 2017-12-25
I have a matrix A in which I have number of days in first column and corresponding data in the second column. For example, A (1,1) = 1; A (1,2) = 0.1; A (2, 1) = 31; A (2, 2) = 0.2; A (3, 1) = 365; A (3, 2) = 0.25; The values in the first column 1, 31, and 365 are the days of a year i.e. January 1, January 31, and December 31, respectively. The values in the second column are the data for the corresponding days. For many days of the year, data is not available so the matrix A is incomplete. Now I want to create another complete matrix of size 365*2 (365 is the total no. of days in a year) in which I want to fill the rows with corresponding data from A when the data is available and fill with NaN when the data is not available. For example, I want to fill all days with NaN except Jan 1, Jan 31, and Dec 31 in this case since I don't have data for those period. Could you please advise a neat way to do this?

请先登录，再回答此问题。

回答（1 个）

Sagar
Sagar 2017-12-25
编辑：Sagar 2017-12-25
I finally did it although using a loop:
%create a index column first
first_nan(:, 1) = 1:365;
%compare the A matrix values with NaN matrix and create a new matrix
for i = 1:365;
for j = 1:365;
if( A (j, 1) == first_nan (i, 1));
result (i, :) = A (j, :);
end;
end;
end;

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by