xor function

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Aseel H
Aseel H 2012-5-5
A = ['010','110','111','011',...];
how calculate XOR as B = xor(010,110) >> B 110 then this result xor with the third sting '111'>>>> 001 then this result xor with fourth string '011' and so on

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回答（2 个）

Walter Roberson
Walter Roberson 2012-5-5
To get you started:
char('0' + (A{1} ~= A{2})
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Walter Roberson
Walter Roberson 2012-5-6
A = ['011' '001'] means the same as
A = horzcat('011', '001'); which is the same as
A = '011001';
Is that what you want, or do you wish to use cell arrays, which would have the advantage of being able to use the code I already gave?
Note: my previous posting was Saturday afternoon in my time zone, after which I had to do grocery shopping and similar activities, after which I had my first evening out since New Years Eve. If you require responses more quickly than volunteers can reasonably be expected to be available, then it is recommended that you hire a consulting firm.
Aseel H
Aseel H 2012-5-6
@Walter Roberson I'm sorry if I disturbed you with my questions

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Andrei Bobrov
Andrei Bobrov 2012-5-5
A = {'010','110','111','011'};
A1 = cellfun(@(x)x-'0',A,'un',0);
vertxor = rem(sum(cat(1,A1{:})>0),2);
or:
A =[...
0 1 0
1 1 0
1 1 1]
vertxor = rem(sum(A>0),2)
ADDED after Aseel's comment
use cell array (array A)
A = {'011' '001' '101'
'000' '110' '010'};
A1 = cell2mat(reshape(cellfun(@(x)x - '0',A,'un',0),size(A,1),1,[]));
B = cellstr(reshape(sprintf('%d%d%d',rem(sum(A1>0,3),2)),size(A,1),[]))
ADDED after Walter's comment:
A1 = cell2mat(reshape(cellfun(@(x)x - '0',A,'un',0),size(A,1),1,[]));
B = mat2cell(reshape(sprintf('%d',rem(cumsum(A1~=0,3),2)),2,[]),[1 1],[3 3 3]);
  2 个评论
Walter Roberson
Walter Roberson 2012-5-6
Andrei, the question requires that the calculation be done step by step, for reasons not stated.
Walter Roberson
Walter Roberson 2012-5-6
Step by step does not allow the cellfun solution at all: the poster (for reasons unknown) requires that the xor of the first two sets of data be fully completed and expressed in character for before the second xor is allowed to be started. Efficiency is not the concern in the question: instead the concern is that it be done step-by-step.
Or at least that's the way *I* interpret the question.

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