loop implementation with two conditions

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A VP
A VP 2018-1-3
回答： Guillaume 2018-1-3
I have a time series data sampled at 100 ms. I would like to pick samples every 1 sec or when difference between 2 consecutive samples is more than 10 and then implement a logic inside this condition. How do I use both these together as an 'if' condition?
Thanks!
  2 个评论
Guillaume
Guillaume 2018-1-3
"How do I use both these together as an 'if' condition?"
Most likely, if is the wrong tool. Can you give an example of "the logic inside this condition"?
A VP
A VP 2018-1-3
I need not necessarily stick to an if-loop. Is there an alternate way to implement it?
The logic inside the condition is to store the samples in a new array.

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回答（1 个）

Guillaume
Guillaume 2018-1-3
Something like this would work:
samples = randi([0 20], 1, 1000); %demo data
indices1s = 1:100:numel(samples); %indices at every 1 s
indicesdiff = find(abs(diff(samples)) > 10); %indices of 1st sample when consecutive sample difference is greater than 10.
newsamples = samples(unique([indices1s, indicesdiff, indicesdiff+1])); %indicesdiff+1 to get the 2nd of the two samples when diff is greater than 10
It's all vectorised operations, so no if needed.

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