problem in struct

2 次查看（过去 30 天）
huda nawaf
huda nawaf 2012-5-6
hi
I have :
x1(1:length(y),1:length(x))=0;
txt(1:length(y),1:length(x))=' ';
mat=struct('scor',x1,'pointer',txt);
mat.pointer(1,1:end)='none'
??? Subscripted assignment dimension mismatch.
how resolve this problem?

请先登录，再回答此问题。

采纳的回答

Image Analyst
Image Analyst 2012-5-6
First of all, y is not defined. And what is the size of mat.pointer? Set a breakpoint on the line (I know you know how to do this because you've been around here long enough), and do this:
size(mat.pointer)
If it's not a 1 row by 4 column character array, then the size of mat.pointer and 'none' don't match. And, needless to say, because you're using "end" mat.pointer must already exist, which it might because I can tell you've left out some code.
  3 个评论
显示 1更早的评论
huda nawaf
huda nawaf 2012-5-6
in fact , my problem is :
i do not want use for in my code so I converted these commands:
for j=1:length(x)
mat(1,j).scor=x1(1,j);
mat(1,j).pointer='none';
end
into:
mat(1,1:end).scor=0;
mat(1,1:end).pointer='none';
when do that get
??? Index exceeds matrix dimensions.
Error in ==> alig_waterman at 71
up_scor=mat(i-1,j).scor+gap;
where i=j=2 in this step
note:length(x)=length(y)=2
x1(1:length(y),1:length(x))=0;
txt(1:length(y),1:length(x))=' ';
mat=struct('scor',x1,'pointer',txt);
thanks in advance
Image Analyst
Image Analyst 2012-5-6
I can't reproduce. I ran your code (below) and it generated no error message whatsoever.
x = 1:2; % Make some arbitrary verctor of length 2
y = 3:4; % Make some arbitrary verctor of length 2
% Note:
% length(x) = 2
% length(y) = 2
x1(1:length(y),1:length(x)) = 0
txt(1:length(y),1:length(x)) = ' '
mat = struct('scor',x1,'pointer',txt)
mat(1,1:end).scor = 0
mat(1,1:end).pointer = 'none'
Does that code produce the mat that you desire?

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Data Exploration 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by