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can you please explain the working of following syntax?

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Siddhesh Karbhari
Siddhesh Karbhari 2018-1-14
关闭： MATLAB Answer Bot 2021-8-20
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
it is continuously giving 'Bad cell reference operation.' error.
extrema=zeros(1,4*number);
idx= extrema==0;
extrema(idx)=[];
extr_volume=length(extrema)/4;
for i=1:extr_volume
x=floor((extrema(4*(i-1)+3)-1)/(n/(2^(extrema(4*(i-1)+1)-2))))+1;
y=mod((extrema(4*(i-1)+3)-1),m/(2^(extrema(4*(i-1)+1)-2)))+1;
rx=x+1;
ry=y+1;
rz=extrema(4*(i-1)+2);
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
size(z)
if(abs(z)<threshold)
extrema(4*(i-1)+4)=0;
end
end

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回答（1 个）

Star Strider
Star Strider 2018-1-14
The code you posted does not make sense. It sets ‘extrema’ to an empty array, so all references to elements of ‘extrema’ would throw errors, because they do not exist.
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Star Strider
Star Strider 2018-1-14
I cannot run the code that you attached.
I will delete my Answer in a few hours.
Walter Roberson
Walter Roberson 2018-1-14
We do not have your b.jpg to test with. I copied the demo image car2.jpg to b.jpg and ran the code without difficulty.
"Bad cell reference operation" is not a MATLAB error message. Is it possible that you were running under Octave?

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