splitting a char with no delimiter

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Stephen Devlin
Stephen Devlin 2018-1-15
编辑： Stephen Devlin 2018-1-15
Hi,
Does anyone know how to split a four character cell array string into 2(or better 4) separate strings? A= 'A5C9' %splitting into A1=A5 A2=C9
or even better something like A(1)=A A(2)= 5 A(3)= C A(4)= 9 so that I could use them to index a larger array?
For clarity this question was incorrectly posed, the problem was having a char within a cell, and needing to extract the char and index it. My bad for not realising the differences between strings and chars and should not have written {'...'}, much thanks to all who helped clarify.
Best regards
Steve
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Stephen23
Stephen23 2018-1-15
编辑：Stephen23 2018-1-15
"I am not sure why my cell, which tells me it is a string"
Because cell arrays can contain any other data types it actually tells us nothing about the class of its contents.
"I am not sure why my cell, which tells me it is a string, does not have the A(4)=9"
Because what you appear to have is a char vector in a cell array. And clearly it makes no sense to try to access the individual characters while it is still in the cell (so you need to use some cell indexing first). But this is all speculation, because so far you have told/shown us about four different explanations of what you have (title says char, text says string, example shows cell with char). It might be easiest for everyone if you simply uploaded the complete variable in a .mat file for us to look at.
Stephen Devlin
Stephen Devlin 2018-1-15
Yes Stephen, that is what I was not aware of until you pointed it out, I now know what I was doing wrong. Very much appreciate your help with this.

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Guillaume
Guillaume 2018-1-15
when I look in my code A(1) gives me 'A2C9', not the individual 'A
As I pointed out
A = {'A2C9'}
is not the same thing as
A = 'A2C9'
The former is a cell array. A container, which in this case has only one element, a char array. If your cell array only ever has one element, then you don't need it.
Note that if
A = {'A2C9'}
then A(1) is still {'A2C9'}, exactly the same cell array. Older versions of matlab did not display the enclosing {}, a source of confusion. Newer versions of matlab no longer do this. To get the content of the cell array, you use {} to index it:
>> A = {'A2C9'}
A =
1×1 cell array
{'A2C9'}
>> A{1}
ans =
'A2C9'
>> A{1}(1)
ans =
'A'
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Guillaume
Guillaume 2018-1-15
编辑：Guillaume 2018-1-15
From the other comments, it would appear you have A as
>>A = {'A2C9', 'A1C3_', 'and maybe more'}
A =
1×3 cell array
{'A2C9'} {'A1C3_'} {'and maybe more'}
This is a cell array of char arrays, which you could call a cell array of strings since it appears you're on an older version of matlab.
You can access the individual strings using {} indexing. This returns the content of the cell you index:
>> A{1}
ans = 'A2C9'
>> A{2}
ans = 'A1C3_'
The use of {} is very important. If you use A(1) instead you get a subset of the cell array. It is still a cell array. In newer versions of matlab this is made clear:
>> A(1)
ans =
1×1 cell array
{'A2C9'}
Once you've indexed into a cell using {}, you have a char array that you can index normally using ():
>> A{1}(1)
ans = 'A'
>>A{1}(2)
ans = '2'
>>A{2}(5)
ans = '_'
Stephen Devlin
Stephen Devlin 2018-1-15
Yes, this is the point I was not aware of, I thought chars and strings were almost synonyms, I didn't;t appreciate I could extract the char and then index it. If you put this as an answer I will accept this.

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