this is my code and it has a problem while calculating kafa=y2/y12

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waqas muhammad 2018-1-17

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评论： per isakson 2018-1-17

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chi.m

kafa=y2/y12. but it gives error.. Matrix dimensions must agree.

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Walter Roberson 2018-1-17

You probably need y2./y12

waqas muhammad 2018-1-17

but it gives error.. dimensions must agree

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per isakson 2018-1-17

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编辑：per isakson 2018-1-17

在 MATLAB Online 中打开

Error using  / 
Matrix dimensions must agree. 
>> whos y2 y12
  Name       Size             Bytes  Class     Attributes
  y12        1x450             3600  double              
  y2        15x1                120  double              
>>

What kind of result do you expect from y2/y12 ?
See Debug a MATLAB Program

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per isakson 2018-1-17

I don't understand the meaning of your comment.

per isakson 2018-1-17

It would help if you make an implementation based on nested for-loops.

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waqas muhammad 2018-1-17

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bsxfun(@rdivide,A,B(:))... this can solve my problem but the number of elements in row and column are different now. so what can i do for this problem?

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waqas muhammad 2018-1-17

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sir, y2 is 15x1 while y12 is 450x1, kafa=y2/y12. i need the result of y2/y12. i mean, row to column division,not elementwise division. y2 has 15 rows while y12 has 450 columns. now i need to divide these 15 rows of y2 by 15 columns of y12.