Implicit function inside a loop.
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I want to plot a curve between err and b for different values of b.
- I have kept the values of i to be a constant for the inner iteration, and I want to sum up the error ( square )
- In 'o' and 'p'for different values of 'i' and finally I want to plot err vs b. such that i get a minimum to this curve at a certain 'b'.
sum =0;
err =0;
for b= 0:1:40
for i= 0:1:50
f1 = @(o,i) (sind(b+i) + sind(b-o)) -( 1.180/0.04 + sqrt.((1.140/0.04 - 2*sind(b)).^2 - (cosd(b-o)- cosd(b+i)).^2));
f2 = @(p,i) cotd(p-3.34) - cotd(i-1.07) - (1.180/(1.540 - 0.300));
sum = sum + (o - p).^2;
end
err = sqrt(sum/50);
plot (b,err);
hold on
end
回答（1 个）
Walter Roberson
2018-1-21
total = 0;
err = 0;
bvals = 0:1:40;
for b = bvals
subtotal = 0;
for i= 0:1:50
f1 = @(o,i) (sind(b+i) + sind(b-o)) -( 1.180/0.04 + sqrt.((1.140/0.04 - 2*sind(b)).^2 - (cosd(b-o)- cosd(b+i)).^2));
f2 = @(p,i) cotd(p-3.34) - cotd(i-1.07) - (1.180/(1.540 - 0.300));
subtotal = subtotal + (o - p).^2;
end
err = sqrt(subtotal/50);
plot(bvals,err);
hold on
total = total + subtotal;
end
But why do you define f1 and f2 when you do not use them? And you have not defined o or p but you try to add their squared difference to the total?
3 个评论
Image Analyst
2018-1-21
And even if you did use them, why do you want them to be defined inside a loop instead of at the top of your program?
And don't use sum as the name of your variable since it's a built in function.
Anshuman S
2018-1-21
Anshuman S
2018-1-21
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2018-1-21
2018-1-21
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