How do I sort data by appending a value to an array that may or may not exist?

Question

Matt Brown 2018-1-26

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/379242-how-do-i-sort-data-by-appending-a-value-to-an-array-that-may-or-may-not-exist

回答： Walter Roberson 2018-1-26

I have a large data set that I need to sort into several categories. I have attempted to use the exist command and some if/else statements to determine if it already exists. If it does not, then the variable is created and stored. If it does exist, the value is appended onto the end of the existing array... You will have to forgive the trivialness of the example, it would have been too complicated to share my actual code on this. However, this example does illustrate the issue.

input={'A','A','B','B';5,6,7,8;50,60,70,80;500,600,700,800};
[m,n]=size(input)
for j=1:n
    if strcmp(input{1,j},'A')==1
        if exist('data.A.row2')==0
            data.A.row2=input{2,j};
        else
            data.A.row2(end+1)=input{2,j};
        end
        if exist('data.A.row3')==0
            data.A.row3=input{3,j};
        else
            data.A.row3(end+1)=input{3,j};
        end
        if exist('data.A.row4')==0
            data.A.row4=input{4,j};
        else
            data.A.row4(end+1)=input{4,j};
        end
    elseif strcmp(input{1,j},'B')==1
        if exist('data.B.row2')==0
            data.B.row2=input{2,j};
        else
            data.B.row2(end+1)=input{2,j};
        end
        if exist('data.B.row3')==0
            data.B.row3=input{3,j};
        else
            data.B.row3(end+1)=input{3,j};
        end
        if exist('data.B.row4')==0
            data.B.row4=input{4,j};
        else
            data.B.row4(end+1)=input{4,j};
        end
    end
end
**

This is confusing to me because if I simply enter the following commands into the command line it will append values as I expected. I know it is something stupid on my end, I am just not sure what it is.

data.A.row2=5;
data.A.row2(end+1)=6;
data.A.row3=50;
data.A.row3(end+1)=60;
data.A.row4=500;
data.A.row4(end+1)=600;
data.B.row2=7
data.B.row2(end+1)=8
data.B.row3=70
data.B.row3(end+1)=80
data.B.row4=700
data.B.row4(end+1)=800