How to replace random integers with the alphabet (1=A, 2=B, and so on)

3 次查看（过去 30 天）
Jaime Vera
Jaime Vera 2018-2-5
评论： Jaime Vera 2018-2-5
Hi, Thank you for helping me
I am trying to replace a square matrix of random integers with the alphabet
For instace: A = [1 2; 3 5] should give you A = [A B; C E]
My code is:
clear all; clc;
n = input('Choose your square matrix dimension: ')
N = round((27)*rand(n))
A = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
for kk = 1:length(N)*2
N(kk) = A(kk);
end
N
I do not know how to replace the numbers with the alphabet.
Could you help, please?
Thank you very much
Have a nice day.

请先登录，再回答此问题。

采纳的回答

Guillaume
Guillaume 2018-2-5
An easiest way to generate random integers is to use randi. As for your replacement it's achieved with simple indexing:
n = input('Choose your square matrix dimension: ');
N = randi(26, n);
A = 'A' : 'Z';
%replacement, note that this requires that all N are strictly positive integer:
NewN = A(N)

更多回答（1 个）

Walter Roberson
Walter Roberson 2018-2-5
output = repmat(' ', size(N));
and then
output(kk) = A(N(kk));
However, notice that your N includes values that are 0: if the rand() produces a value less than 1/54 then multiplying by 27 would give less than 1/2 and round() of that would be 0.

类别

在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by