how do i store a matrix value inside a parfor loop?

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Naveen kumar Elumalai
评论： ahmad eldeeb 2022-11-18
I wanted to use the A matrix outside the parfor loop for further computation, i get an error stating "cannot run due to way variable A", is there any solution to this problem ??is there any other way to save the matrix???
thank you
N=50;
parfor n=1:Nc
b=rand(300,103);
[Q,R]=qr(b,0);
A((n-1)*(N+1)+1:n*(N+1),:)=R
end

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采纳的回答

Greg
Greg 2018-2-17
Pre-allocate A to store each R along the third dimension, then reshape it outside the loop. Iterations of parfor can't use indexing that depends on other iterations of the loop (i.e., n-1).
A = zeros(N+1,numColsofR,Nc);
parfor ...
A(:,:,n) = R;
end
reshape(permute(A,[1,3,2]),[],numColsofR);
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