I have a string array ["Black" "Brown" "Red" "Orange" "Yellow" "Green" "Blue"] and I want to replace the colors with values 0, 0 0, 0 0 0, ... until i get to 0 0 0 0 0 0 0.

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ciro saravia 2018-2-17

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回答： the cyclist 2018-2-18

Array should look like [0, 0 0, 0 0 0, 0 0 0 0, 0 0 0 0 0, 0 0 0 0 0 0, 0 0 0 0 0 0 0] instead of the original one containing colors.I am unsure how to do it.

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the cyclist 2018-2-18

编辑：the cyclist 2018-2-18

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Can you add a little more detail? This is not Twitter, so please make it easy on us.

For example, is the output a numeric matrix, like

[0 0 0 0 0 ...]

? Or is it a string matrix, such as ...

out = ["0" "0 0" "0 0 0"]

Also, does it matter if a color is repeated?

ciro saravia 2018-2-18

string matrix, out = ["0"...]

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Answer 1

the cyclist 2018-2-18

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Here is one way:

s = ["Black" "Brown" "Red" "Orange" "Yellow" "Green" "Blue"];
L = length(s);
Z = strings(1,7);
Z(1) = "0";
for ns = 2:L
    Z(ns) = strcat(Z(ns-1)," 0");
end

I don't have much experience working with strings, so I expect there is a more efficient way.

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I have a string array ["Black" "Brown" "Red" "Orange" "Yellow" "Green" "Blue"] and I want to replace the colors with values 0, 0 0, 0 0 0, ... until i get to 0 0 0 0 0 0 0.

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I have a string array ["Black" "Brown" "Red" "Orange" "Yellow" "Green" "Blue"] and I want to replace the colors with values 0, 0 0, 0 0 0, ... until i get to 0 0 0 0 0 0 0.

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