How do I plot a point at the x intercept on this graph?

Question

Rhianne Tallarico 2018-2-20

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/383735-how-do-i-plot-a-point-at-the-x-intercept-on-this-graph

回答： Are Mjaavatten 2018-2-20

e=1;
sigma=0.154;
r=linspace(0.154,1,100);
U = @(e,sigma,r) 4*e*((sigma./r).^12)-((sigma./r).^6);
norm_r = r./sigma;
figure
plot(norm_r,U(e,sigma,r))
title('Lennard-Jones Potential')
xlabel('Distance (nm)')
ylabel('Potential Energy')

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dpb 2018-2-20

Not sure precisely what you want to add where???

Rhianne Tallarico 2018-2-20

This code plots a curved line, I am looking to find the x intercept value of the line, and plot a marker at that point. Thanks!

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Answer 1

Are Mjaavatten 2018-2-20

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/383735-how-do-i-plot-a-point-at-the-x-intercept-on-this-graph#answer_306100

在 MATLAB Online 中打开

Let U be a function of r only and find the solution to U(r) = 0:

e=1;
sigma=0.154;
r=linspace(0.154,1,100);
U = @(r) 4*e*((sigma./r).^12)-((sigma./r).^6);
norm_r = r./sigma;
figure
plot(norm_r,U(r))
title('Lennard-Jones Potential')
xlabel('Distance (nm)')
ylabel('Potential Energy')
norm_r_0 = fzero(U,1)/sigma;
hold on; plot(norm_r_0,0,'*r')