change the element-by-element organization into a plane organization

2012 5 15
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Hello
I have an array <20000x1 struct> in element-by-element organization. Each of the 20000 entries has more than 30 fields.
I would like to change the element-by-element organization into a plane organization.
I found how to do it from plane to element-by-element ( http://www.mathworks.com/matlabcentral/answers/4581-deleting-the-i-th-entry-from-all-fields-of-a-struct) but I cannot figure out how to do it in the opposite way.
Could you help me, please?
Thank you very much
Claudia

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Claudia
Claudia 2012-11-8
long time ago I found my own solution but forgot to put it here. So, here it is:
folder = ['/scratch ...']
fields = fieldnames (datastructold) ;
for f = 1:size(fields,1) ;
varname = genvarname(fields{f}) ;
extract = {datastructold.(varname)};
datastructnew.(varname) = extract ;
end
v = genvarname([ 'name' ]) % name for variable
S.(v) = datastructnew
save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

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Claudia
Claudia 2013-1-29

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long time ago I found my own solution but forgot to put it here. So, here it is:
folder = ['/scratch ...']
fields = fieldnames (datastructold) ;
for f = 1:size(fields,1) ;
varname = genvarname(fields{f}) ;
extract = {datastructold.(varname)};
datastructnew.(varname) = extract ;
end
v = genvarname([ 'name' ]) % name for variable
S.(v) = datastructnew
save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

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Walter Roberson
Walter Roberson 2012-5-15

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struct2cell(), then either cell2mat() or expand the cell within a vertcat() or horzcat().
However, if the fields are not all exactly the same size or are of mixed numeric type involving more than one integer data type, then you are going to have problems.

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Claudia
Claudia 2012-5-18
Hi Walter
Thank you for your answer. I tried what you suggested.
But for cell2mat all contents of the input cell array must be of the same data type.
And vertcat() and horzcat() did not change anything at all.
So, at the end I missed the step to get the structure with plane organization.
It would be nice if you could explain that step.
Thanks, Claudia

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Sean de Wolski
Sean de Wolski 2012-11-8
编辑：Sean de Wolski 2012-11-8

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So if this is a simple example of your struct:
S = struct('field1',num2cell(1:10),'field2',num2cell(repmat(pi,1,10)))
Then I would recommend using:
S2 = squeeze(struct2cell(S))
To now have a 2x10 cell array.

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