comparing elements of a cell array based on another cell array

1 次查看(过去 30 天)
hi
array1 = {[2,5];[1,3,4]}
array2= {[1,4],[1,5],5,4,[3,5,2]}
I need to perform a comparison. 1st element of array1 is [2,5] which is at position 1 in array1. so it will take 1st value in array2 [1,4] and compare it with 2nd and 5th value in array2 which are [1,5] and [3,5,2]. and in result it will take out the one which has at least one value in common with [1,4] as here we will get 2 because 2nd element [1,5] has '1' common with [1,4].
for 2nd element in array1 which is [1,3,4], it will take 2nd value of array2 and compare it with 1st,3rd and 4th value and [1,3] will be in result because 4th value which is [4] has nothing in common with [1,5].
so output will be:
ResultantantArray = {2,[1,3]}
i hope i have explained it well. kindly help on this.
Thanks in anticipation

采纳的回答

Andrei Bobrov
Andrei Bobrov 2018-3-6
编辑:Andrei Bobrov 2018-3-6
a1 = {[2,5];[1,3,4]};
a2= {[1,4],[1,5],5,4,[3,5,2]};
n = numel(a1);
out = cell(n,1);
nn = cellfun(@numel,a2);
for ii = 1:n
jj = a1{ii};
t = repelem(jj,nn(jj));
out{ii} = unique(t(ismember([a2{jj}],a2{ii})));
end
  3 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by