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is my solution wrong?

2 次查看（过去 30 天）
Mohammad Adeeb
Mohammad Adeeb 2018-3-10
关闭： MATLAB Answer Bot 2021-8-20
close all;
clear all; %#ok<*CLSCR>
clc;
syms r z;
p1=input('specify the pol cofficent');
s=input('specify the operation','s');
p2=input('specify the second poly');
L_1=length(p1);
L_2=length(p2);
L=abs(L_1 - L_2);
if L_1>L_2
z=zeros(1,L_2);
A=[z p2];
end;
if L_1<L_2
z=zeros(1,L_1);
A=[z p1];
end;
hold on;
while s~='=';
if s=='+'
r= p1+p2;
elseif s=='-';
r= p1-p2;
elseif s=='*';
r= p1.*p2;
elseif s=='/';
r=p1./p2;
elseif s=='=';
print(r)
end;
ezplot(r,[-2,2]);
end;
hold off;
if s=='=';
r = pol_1;
end;
ezplot (r,[-2,2]);
  2 个评论
Geoff Hayes
Geoff Hayes 2018-3-10
Mohammad - what are your inputs? what is the solution given by your code?
Your use of a while loop seems suspect. It seems that you might get stuck in the loop if the character string s is not '='. Also, try to avoid using equality (i.e. ==) for string comparisons. Instead use strcmp or strcmpi.
John D'Errico
John D'Errico 2018-3-10
Surely you can test your solution. Code that is wrong produces errors. It produces strange, unexpected results. So what do you think? Is it right?
Will your code work on two polynomials of different order?
Why do you create the variable A if you do not use it?
Is it correct that the product of two polynomials is the product of their coefficients?
There are lots of problems that I see here. So, yes, your solution is wrong.

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