Averaging Matrix and store it in a new matrix

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matlab_newbie
matlab_newbie 2012-5-18
Assuming i have a 125x125 image. and i want to create new matrices where each point consists of the average of the surrounding 8 points and itself. but ignoring the average for the pixels on the edge for simplicity.
x = imread('image.png');
[rows,cols] = size(x);
for r = 1:rows;
for c = 1:cols;
%it does not seem working by using to inbult mean function here since its a m x n matrix i want to calculate.
end
end
so for example, i have a matrix of
x = [1 2 3 4; 5 6 7 8; 9 10 11 12;13 14 15 16]
m = x(1:3,2:4)
z = mean(x(1:3, 2:4))
---------------------------------
x =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
m =
2 3 4
6 7 8
10 11 12
z =
6 7 8
but what i really want of z is z = (2+3+4+6+7+8+10+11+12)/9 = 7 is there anyway to do this?

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回答（4 个）

Daniel Shub
Daniel Shub 2012-5-18
Assuming your data x is N x M and not a color image
y = conv2(x, ones(3, 3) / 9, 'same');
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matlab_newbie
matlab_newbie 2012-5-18
it works well, but can i use any loop plus mean function to achieve this?
lets say i cant use the conv2() function. thank you very much
Daniel Shub
Daniel Shub 2012-5-18
@IA and Sean, I meant SAME and not VALID. While newbie wanted to ignore the edges for simplicity, I wanted to show that the edges could be handled.

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Junaid
Junaid 2012-5-18
try this if it works for you.
x = [1 2 3 4; 5 6 7 8; 9 10 11 12;13 14 15 16];
f = fspecial('average',3,3); % create filter of 3 x 3
b = imfilter(x,f);
and to see the different configuration to handle boundary values, you can see the documentation of imfilter.
Image Analyst
Image Analyst 2012-5-18
Try this:
% Get the average, avoiding any edge effects due to partial masking.
outputArray = conv2(inputArray, ones(3)/9, 'valid');
% Now get "z" which they defined as the mean
% of each column (averaging going down the rows)
z = mean(outputArray, 1);
% Get their second definition of z
% which is the mean of all the elements in their first z:
z = mean(z);
But isn't this second z just the same as
z = mean2(x(2:end-1, 2:end-1));
????? It gives a single number that is the mean of x ignoring the edge rows and edge columns.
  1 个评论
matlab_newbie
matlab_newbie 2012-5-18
thank you very much for trying to help!! it kind of helps!! as i hv never knew the 'mean2' function.
but, that only gives one single averaged number of the entire matrix.
what i want to achieve is, have a average for every 3x3 array inside this entire 125x125 matrix and store(or output) it into a new array (or matrix i should say).
so for example,
x =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
i want [1 2 3;5 6 7;9 10 11] averaged which is = 6. and [2 3 4;6 7 8;10 11 12] = 7, and [5 6 7;9 10 11;13 14 15] = 10. and so on. then store these values into a new array ... which maybe z = [6 7 10]
it pretty confusing, so we are kinda ignoring to take the average of the edge columns and rows, but when we calculate the average inside the matrix should still include the edges. which 'taking the average of every 3x3 array in the entire matrix of 125x125' should be able to express this idea..but i have no idea how...im definitely thinking i should loop it somehow. and how can i store the output in a new variable(so create a new matrix)?
can you please help, thank you very much.

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Daniel Shub
Daniel Shub 2012-5-18
Assuming you really want to do this with loops and mean, presumably for homework, you are on the correct track. Te thing you missed is the the mean of 6 7 8 is 7, the answer you want. S just replace
z = mean(x(1:3, 2:4))
with
z = mean(mean(x(1:3, 2:4)))
or even better
z = mean(m(:))

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