Entering a vector in a function with if else statement
1 次查看(过去 30 天)
显示 更早的评论
Hi Matlab community.
I made this function that should sort out data that differs more than +/- 20 % giving it "NaN" if it does. If the previous measurement varied more than 20 % it should should not do so, which i tried with the command: "(sorted_data(i-1)==NaN) && (i>1)" but when I use the debugger it does not enter this statement even though it is true. How come it won't enter this? Thanks for the help!
Kind Regards
function sorted_data=sort_for_outliers(data)
sorted_data=zeros(length(data),1);
for i=1:length(data)
if i==1
sorted_data(i)=[data(i)];
elseif (sorted_data(i-1)==NaN) && (i>1)
sorted_data(i)=[data(i)];
elseif data(i)>1.20.*data(i-1)
sorted_data(i)=[NaN];
elseif data(i)<0.80.*data(i-1)
sorted_data(i)=[NaN];
else
sorted_data(i)=[data(i)];
end
end
end
1 个评论
Torsten
2018-3-12
At the beginning of your function, you set "sorted_data" to zero. Thus sorted_data(i-1) will not be NaN.
Best wishes
Torsten.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!