Variable 'x_opt' is not fully defined on some execution paths.
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i am write this code in userdefined Simulink function For model predictive control but this code has some error so what i have too do.
function [Sa,Sb,Sc] = control(I_ref,I_meas)
2 % Variables defined in the parameters file
3 % Sampling time of the predictive algorithm [s]
4 Ts = 25e-6;
5 % Load parameters
6 R = 10; % Resistance [Ohm]
7 L = 10e-3; % Inductance [H]
8 e = 100; % Back-EMF peak amplitude [V]
9 f_e = 50*(2*pi); % Back-EMF frequency [rad/s]
10 Vdc = 520; % DC-link voltage [V]
11 % Current reference
12 I_ref_peak = 10; % Peak amplitude [A]
13 f_ref = 50*(2*pi); % Frequency [rad/s]
14 % Voltage vectors
15 v0 = 0;
16 v1 = 2/3*Vdc;
17 v2 = 1/3*Vdc + 1j*sqrt(3)/3*Vdc;
18 v3 = -1/3*Vdc + 1j*sqrt(3)/3*Vdc;
19 v4 = -2/3*Vdc;
20 v5 = -1/3*Vdc - 1j*sqrt(3)/3*Vdc;
21 v6 = 1/3*Vdc - 1j*sqrt(3)/3*Vdc;
22 v7 = 0;
23 v = [v0 v1 v2 v3 v4 v5 v6 v7];
24 % Switching states
25 states = [0 0 0;1 0 0;1 1 0;0 1 0;0 1 1;0 0 1;1 0 1;1 1 1];
26 % Optimum vector and measured current at instant k-1
27 persistent x_old i_old
28 % Initialize values
29 if isempty(x_old)
30 x_old = 1;
31 end
32 if isempty(i_old)
33 i_old = 0+1j*0;
34 end
35 g_opt = 1e10;
36 % Read current reference inputs at sampling instant k
37 ik_ref = I_ref(1) + 1j*I_ref(2);
38 % Read current measurements at sampling instant k
39 ik = I_meas(1) + 1j*I_meas(2);
40 % Back-EMF estimate
41 e = v(x_old) - L/Ts*ik - (R - L/Ts)*i_old;
42 % Store the measured current for the next iteration
43 i_old = ik;
44 for i = 1:8
45 % i-th voltage vector for current prediction
46 v_o1 = v(i);
47 % Current prediction at instant k+1
48 ik1 = (1 - R*Ts/L)*ik + Ts/L*(v_o1 - e);
49 % Cost function
50 g = abs(real(ik_ref - ik1)) + abs(imag(ik_ref - ik1));
51 % Selection of the optimal value
52 if (g<g_opt)
53 g_opt = g;
54 x_opt = i;
55 end
56 end
57 % Store the present value of x_opt
58 x_old = x_opt;
59 % Output switching states
60 Sa = states(x_opt,1);
61 Sb = states(x_opt,2);
62 Sc = states(x_opt,3);
63end
2 个评论
Walter Roberson
2022-10-27
if (g<g_opt)
g_opt = g;
x_opt = i;
end
Suppose that condition is never true, then what is x_opt set to?
采纳的回答
Walter Roberson
2018-3-13
The message is correct. You do not define the value of x_opt under the circumstance that none of the computed g values are less than the 1e10 that you initialize g_opt to.
5 个评论
Noemi Hernandez-Oliva
2020-1-9
Hello Hussain can you tell me too what is the solution, I sent you an email
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