How do I ask the user for a persons name and output the birthday of the person?

Question

Nathan Kidd 2018-4-6

0
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https://ww2.mathworks.cn/matlabcentral/answers/393159-how-do-i-ask-the-user-for-a-persons-name-and-output-the-birthday-of-the-person

回答： Elias Gule 2018-4-6

I am working on an assignment where I am given a .csv file with names in column one, birthmonth in column 3, and birthday (day of month) in column 4. I have to do a lot of things but what I am having trouble doing is making a system that allows the user to input a name and receive the birthday.

Eventually I put the birthday in a format that is simply days into the year (jan 5 = 5, Dec 31 = 365) and compare that to today's date to see how many days have passed/have yet to come since/until the persons birthday.

to put it simply, the user must: input a name, receive birthday (in the weird format).

Here is what I have so far, but I can't get it to work and I don't even think I'm on the right track:

input_file='employees.csv'; % in these lines I attempt to read the .csv 
file=fopen(input_file);     % into the program
data=textscan(file,'%s%s%d%d%f','delimiter',','); % I use a , delimiter
fclose(file); % close the file because that's just what you do
num_rows=size(data{1});     % This finds the number of rows in the .csv
employee.first_name=data{1}; % this creates a structure full of first names?
for i=1:num_rows  % This prints out the whole .csv file
    fprintf('%s %s, ',data{1}{i},data{2}{i});
    fprintf('%d/%d  %.2f\n',data{3}(i),data{4}(i),data{5}(i));
end
%this outputs:
%Donald Trump, 6/14  400000.00
%Mickey Mouse, 11/18  10000.00
%Ada Lovelace, 12/10  5000.00
%Justin Bieber, 3/1  125000.00
%Benjamin Franklin, 1/17  15000.00
%Angela Merkel, 7/17  234400.00
%columns 1 through 5 are: firstname, lastname, birthmonth, birthday, income
today=clock     %just assigning some values for some obvious variables 
year=today(1)   % year = what year it is etc
month=today(2)
day=today(3)
%this gives me the amount of days its beensince the start of the year
today_num=datenum(date)-datenum(year,1,0) 
d_in_m=[31,28,31,30,31,30,31,31,30,31,30,31] %this is a matrix of the days in each month
employee.first_name=data{1}; %assigning some values to two structures
employee.last_name=data{2};
birth_month=data{3};         %assigning some values to two cell arrays (I think)
birth_dayofmonth=data{4};
%what I'm trying to do here is create an array called "index" that holds
%the birthday in the format of days into the year (jan5=5, Dec31=365) but I
%dont know if this would even help me if it worked.
for i=1:num_rows
    index=0;
    for j=1:birth_month(i)-1
        index=d_in_m(j)+index
    end
    index=index+birth_dayofmonth
end
%this outputs a lot of similar numbers but the birthdays in the files are
%far away from each other so this shouldn't be the case.
%index =
    %6×1 int32 column vector
     %195
     %199
     %191
     %182
     %198
     %198  if true
    % code
  end