The error "Matrix dimensions must agree"

Question

Ashbub 2018-4-17

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/395392-the-error-matrix-dimensions-must-agree

评论： Ashbub 2018-4-17

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hi all

I am getting this error

"Matrix dimensions must agree.
Error in TwoDTensorRev4 (line 106)
TbinAreaSum= double(TbinAreaSum)+double(binAreaSum);"

Here is the code and the input file is attached as well. Please suggest. Thank you.

s=load('C20-28D-150kPa-voidForFabricStudyXZ.mat'); 
fieldname=fieldnames(s)           
m=s.Avizo_C20_28D_150kPa_voidForFabricStudyXZ_mat; 
sm=squeeze(m);                  
sm = bwareaopen(sm,2,4);          
szdim=size(sm,3);                
slices=szdim;                     
slices=200;                       
pieslice=25;                      
indcs=zeros(size(sm,1),size(sm,2));
porientd=zeros(slices,1);    
num=zeros(slices,1);       
perea=zeros(slices,1) ;
avgperea=zeros(slices,1);
edges=zeros(1,pieslice,1);
sumareapd=zeros(slices,1); 
TbinAreaSum=zeros(pieslice-1,1);
for jj=1:slices
    [L2,num(jj,1)] = bwlabel(sm(:,:,jj)); 
areap=zeros(num(jj,1),1);        
areapd=zeros(2.*num(jj,1),1);
areapactual=zeros(num(jj,1),1);
binAreaSum=zeros(pieslice-1,1);
perip=zeros(num(jj,1));     
vector=zeros(num(jj,1),2);   
vectord=zeros(2.*num(jj,1),2); 
cent=zeros(num(jj,1),1);      
hbin=zeros(1,2.*num(jj,1));   
thetap=zeros(1,2.*num(jj,1)); 
sumperea(jj)=0;
for ii=1:num(jj,1)           
areao=regionprops((L2==ii),'area'); 
perio=regionprops((L2==ii),'perimeter'); 
areap(ii,1)=areao.Area./(areao.Area);
areapactual(ii,1)=areao.Area;          
perip(ii,1)=perio.Perimeter;            
perea(ii,jj)=perip(ii,1)./areapactual(ii,1);
coeff=pca(indcs);       
vector(ii,1)=coeff(2,1);               
vector(ii,2)=coeff(1,1);               
sumperea(jj)=sumperea(jj)+perea(ii,jj);
end
sumareapd(jj,1)=2.*sum(areap(:,1)); 
avgperea(jj,1)=sumperea(jj)./num(jj); 
vectord=[vector;-vector]; 
areapd=[areap;areap];      
for mm=1:2.*num(jj,1)
thetap(mm)=atan2d(vectord(mm,2),vectord(mm,1));       
       if (thetap(mm) < 0)
            thetap(mm)=360+thetap(mm);
        else
            thetap(mm)=thetap(mm);
        end;
end;
for nn = 1:pieslice                       
edges(1,nn)=(nn-1).*pi./((pieslice-1)./2.0);
end
hbin = discretize(round(deg2rad(thetap),10),round(edges,10));
binAreaSum=accumarray(hbin',areapd); 
TbinAreaSum= TbinAreaSum+binAreaSum; 
end

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KSSV 2018-4-17

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Getting different error on running the code:

Undefined function or variable 'indcs'.
Error in Junk (line 38)
coeff=pca(indcs);

Ashbub 2018-4-17

Thankyou. I have defined the indcs. Please have a look.

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Answer 1

Walter Roberson 2018-4-17

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/395392-the-error-matrix-dimensions-must-agree#answer_315507

在 MATLAB Online 中打开

pieslice=25;
TbinAreaSum=zeros(pieslice-1,1);

so TbinAreaSum is (25-1)=24 by 1. You then do not change the contents until the last line where you try

TbinAreaSum= TbinAreaSum+binAreaSum;

binAreaSum was created as

binAreaSum=zeros(pieslice-1,1);

which is also 24 x 1. But you write all over it, in the second last line,

binAreaSum=accumarray(hbin',areapd);

so binAreaSum will only be 24 x 1 if hbin' happens to have 24 unique values in it.

Now you create hbin as

hbin = discretize(round(deg2rad(thetap),10),round(edges,10));

after

for nn = 1:pieslice                       
edges(1,nn)=(nn-1).*pi./((pieslice-1)./2.0);
end

so edges has 25 entries -- but it is not immediately clear that round(edges,10) happens to have 24 unique entries. It might be 25 unique entries; it might be less.

You need to put in a breakpoint before the accumarray and check length(unique(hbin))

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Ashbub 2018-4-17

Thanks a lot. You've hit the right spot. Used histcounts instead of discretize and made few changes to remove the need for using accumarray as well. It did the trick.

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