how to have a loop if for a column in a table

1 次查看(过去 30 天)
I have a table with many columns... I want to iterate into one column, that have many numbers valores. is there someone that can help me?
the pseudocode is
if table.column > number
table.new_column= 'Ok'
else
table.this_new column='nok'
finally i wil have a new columns with ok and nok depending of the valor of the column

采纳的回答

Ameer Hamza
Ameer Hamza 2018-5-14
编辑:Ameer Hamza 2018-5-14
You don't need a for loop, use arrayfun(),
words = {'nok', 'ok'};
table.newColumn = arrayfun(@(x) words((x>number)+1), table.column);
  3 个评论
Jessica Blasco
Jessica Blasco 2018-5-14
ok, this solution works, but i have another question ... in my case, i have 8 types de variables in a column (1..8) for each type i have a value limit,(stored them in a vector) So... limit_value=[ number1, number 2, number 3,....,number 8] i want to evaluate for each type, the value that corresponds in the limit value.
type 1 -> evaluate > number 1
type 2-> evaluate > number 2
....
but i want to have with a loop, it's posible?
thanks!
Ameer Hamza
Ameer Hamza 2018-5-14
It is not clear what you are trying to do but you can access and change values of a table just like a cell array using table{1,1} (first column, first element). Similarly, use can assign as
table{1,1} = 1; % it will assign the value

请先登录,再进行评论。

更多回答(1 个)

Peter Perkins
Peter Perkins 2018-5-14
Ameer's solution works, but arrayfun is really not needed:
words = {'nok', 'ok'};
table.newColumn = words(table.column>number)+1);
But also, a cell array of 'ok' and 'nok' is likely not all the helpful. I'd suggest making a categorical variable:
table.newColumn = categorical(table.column>number,[false,true],{'nok' 'ok});
Like Ameer, I'm not able to fully understand the followup question.
  2 个评论
Jessica Blasco
Jessica Blasco 2018-5-15
i have a vector with 8 numbers,so v=[number1, number2,...., number8] In my column i have 8 categories of number, 1..8...
i would like iterate the column such that for each number in the column i can evaluate if this valor is mayor a his position in the vector...
so...
column
1 evaluate number in position 1 of the vector
1 evaluate number in position 1 of the vector 2 evaluate number position 2 of the vector
3 evaluate number in the position 3 of the vector
4 evaluate number in the position 4 of the vector
2 evaluate number in the position 2 of the vector
1 evaluate number in the position 1 of the vector
5 evaluate number in the position 5 of the vector
I would like iterate this table with a loop for, it's posible??
Peter Perkins
Peter Perkins 2018-5-17
I can't follow this. I suggest you open a new thread, with a short, clear example of what you have and what you want.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by