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Transform a cell of arrays to a table?

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Iris Li
Iris Li 2018-5-15
评论： Iris Li 2018-5-15
How could I get B from A? Thanks!!! The cell2table command couldn't because the element in A is {[1;2;3]}, instead of {[1]},{[2]},{[3]}, which would make it a bit more complicated. I tried cell2table, cell2mat, struct2table...
A = {[1;2;3];[1;2;3];[1;2;3];[1;2;3]}
B = [1,2,3;1,2,3;1,2,3;1,2,3]
A =
4×1 cell array
[3×1 double]
[3×1 double]
[3×1 double]
[3×1 double]
B =
1 2 3
1 2 3
1 2 3
1 2 3
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Iris Li
Iris Li 2018-5-15
I actually have the following function. Para is like A I mentioned in this question, a 4*1 cell. What I want to get is a 4*3 table.
G = findgroups(m,n);
func = @(x,y,z){[z,z.*x(:),z.*x(:).^2]\(z.*y(:))};
Para = splitapply(func,x,y,z,G);
Iris Li
Iris Li 2018-5-15
Sorry I modified the codes in this question just now. Hopefully you'll find it more clear haha.

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2018-5-15
B = [A{:}]'

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