Getting all the real solutions of a 12 variable 12 non-polynomial equations using vpasolve()

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Ratan Rathore
Ratan Rathore 2018-5-24
编辑： Ratan Rathore 2018-5-26
The equation which i want to solve looks like this:
A(y)=(a6*x^5+a5*x^4+a4*x^3+a3*x^2+a2*x+a1)*[log(28/B(y)/(b6*x^5+b5*x^4+b4*x^3+b3*x^2+b2*x+b1))]
where, A(y) and B(y) are real value functions of 'y'
Here, for 12 different sets of(x,y) we are going to get 12 sets of equations. From those equations I want to find the real solutions for a1,a2,a3,a4,a5,a6,b1,b2,b3,b4,b5,b6
I want to get all the real solutions of them. I am getting only a single set of solution for them which is imaginary. I'm only interested in real solutions.
So, If there is any way to solve this problem then please help.
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Walter Roberson
Walter Roberson 2018-5-25
No, it is not possible to get any solutions when so little information is available. To get any further we need to know at least the possible range of values for x and corresponding y and for A(y) and B(y) . For testing period should be I be using, for example, random numbers in the range -10000 to +10000 for everything? Because of the log(), negative B could be a problem unless x is also negative or b6 is negative (thereby making the expression inside the log() positive.)
Ratan Rathore
Ratan Rathore 2018-5-26
编辑：Ratan Rathore 2018-5-26
these are the equations with the values of x and y (Now i reduced them to 10 equations for now and want the closest real possible solutions if not exact) http://textuploader.com/dfe39 ...Yeah you are correct, B should also be positive otherwise it will result in imaginary outcomes

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