problem with parfor variable

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Hello,
i have a large code. I am summarizing the problem using a simple code.
parfor it=1:30
for jt=1:30
a(it,jt)=some_value;
end
end
an error is shown."The variable a in a parfor cannot be classified." why cant matlab classify the variable? why does the variable 'a' fail to become a sliced variable?
Is there any other indexing scheme that can serve my purpose in the above mentioned code?
THANKS IN ADVANCE.
-OBLI

采纳的回答

Thomas
Thomas 2012-6-4
the above code in its simple form works: just preallocate for speed
a=zeros(30,30); % preallocate variable a
parfor it=1:30
for jt=1:30
a(it,jt)=rand(1);
end
end
the error in slicing the variable might come in from the part you probably left out..
  11 个评论
Thomas
Thomas 2012-6-4
I assume you are using Matlab older than R2011a..
oblivious
oblivious 2012-6-5
this problem was resolved in r2011a. i found in the release notes

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