Can one have a function that opens and manipulates more than one file with name containing an array
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If in a script named Overall I have :
angle = input('Which angles (degree) are you targeting: ')
>> [8 7 6 5 4 3 2 1]
followed by calling function:
Tablefliptrial(angle) %line 5
and then a create a separate .m file containing the function
function [desiredOutput] = tablefliptrial(angle)
fileID = fopen('distance',angle,'zenith.plt'); %open file %line 2
%do a bunch of operations towards desired output
desiredOutput = [] %huge matrix
end
Am I allowed to place the value of each angle so that the function reads each file format (i.e. distance1zenith, distance2zenith...) or do I need a different approach? Error given:
Error using fopen
Invalid permission.
Error in Tablefliptrial (line 2)
fileID = fopen('distance',angle,'zenith.plt'); %open file
Error in Overall (line 5)
Tablefliptrial(angle)
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采纳的回答
Ameer Hamza
2018-5-29
编辑:Ameer Hamza
2018-5-29
fopen() can only accept two inputs. The first input is filename and second is the permission. What you are doing, is to give 3 inputs to fopen(). Therefore fopen() is not working. Also each call to fopen() can only open 1 file so you will need to for loop. You need to do it like this
function [desiredOutput] = tablefliptrial(angle)
for i=angles
fileID = fopen(['distance',num2str(i),'zenith.plt']); %open file %line 2
%do a bunch of operations towards desired output
desiredOutput = [] %huge matrix
end
end
note that adding [] have converted the three inputs into one char array of the filename. You can specify the second input to fopen() as permission with which you want to open the file.
4 个评论
Stephen23
2018-5-30
编辑:Stephen23
2018-5-30
Always fclose every file that you fopen in the loop!
It is an very bad practice to leave files open like that: continually opening files can eventually cause MATLAB to crash. The MATLAB documentation specifically advises "When you finish processing the file, close it with fclose(fid).".
Always fclose after processing the files!
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