Undefined function or variable 'v'.??

3 次查看(过去 30 天)
Libby Goodes
Libby Goodes 2018-6-3
评论: Rik 2018-6-6
t=-5:50;
if t<=8
v=10.*(t.^2)-(5.*t);
elseif (t>=8) & (t<=16)
v=624-(5.*t);
elseif (t>=16) & (t<=26)
v=(36.*t)+12.*(t-16).^2;
elseif (t>26)
v=2136.*exp(-0.1.*(t-26));
elseif (t<0)
v=0;
end
plot(t,v)

回答(1 个)

Rik
Rik 2018-6-3
You made the classic mistake of thinking that this set of logical statements would be handled for each element of your vector. But Matlab doesn't work that way, unless you tell it with a for-loop.
The code below uses logical indexing to get the result.
t=-5:50;
v=zeros(size(t));
L=t<=8;
v(L)=10.*(t(L).^2)-(5.*t(L));
L=(t>=8) & (t<=16);
v(L)=624-(5.*t(L));
L=(t>=16) & (t<=26);
v(L)=(36.*t(L))+12.*(t(L)-16).^2;
L=t>26;
v(L)=2136.*exp(-0.1.*(t(L)-26));
L=t<0;
v(L)=0;
plot(t,v)
  3 个评论
Rik
Rik 2018-6-3
The second line pre-allocates the vector v by filling it with zeros. This way we can use the same logical vector for v as for t.
Have you tried reading the documentation for zeros and size?
Rik
Rik 2018-6-6
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