Removing Elements from an Array based on their Position for every 3 Elements

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CharlesB
CharlesB 2018-6-21
评论： CharlesB 2018-6-22
Say I have an array called elements_n:
elements_n = [0, 1];
I have another array called Arr:
Arr = [0, 1, 3, 1, 2, 4];
If any of the first 3 elements of the array Arr are equal to the first element of elements_n which is 0, I would like to delete that element from the array called Arr. I then repeat the same process for the next 3 elements of the Array Arr. So to explain myself better, I will use the following example:
Compare the first 3 elements of array Arr which are 0, 1, 3 to the first element of elements_n which is 0. Since Arr[1] == elements_n[1]. I delete Arr[1] from the array Arr.
Compare the next 3 elements of array Arr which are 1, 2, 4 to the second element of elements_n which is 1. Since Arr[4] == elements_n[2]. I delete Arr[4] from the array Arr. So the elements that should be left in the array Arr are:
Arr = [1, 3, 2, 4];

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采纳的回答

Adam
Adam 2018-6-21
If you are using R2015a or later then this will work:
elements_n = repelem( elements_n, 3 );
Arr( Arr == elements_n ) = [];

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